Admission to Undergraduate Engineering Programs at NITs, IIITs, Other centrally
funded Technical Institutions, Institutions funded by several participating State
Governments, and several other Institutions shall involve the Joint Entrance Examination,
JEE (Main). The JEE (Main) will also be an eligibility test for the JEE (Advanced),
which the candidate has to take if he/she is aspiring for admission to the undergraduate
programmes offered by the IITs.
Normalization Procedure for Class XII Board Marks
In view of large scale variations in the examination system in country, the JEE Interface
Group (JIG) decided that for this year (2013), 50% of Boards marks be normalized by
equating percentile amongst different boards/examining bodies and anchoring them to
All India JEE-Main percentiles, and 50% be normalized by equating each
Board’s/examining Body’s percentile with JEE(Main) percentile marks of respective
Boards /examining bodies.
Accordingly, the detailed procedure for normalization of Board marks will be as follows:-
i. Note down the aggregate marks (A0) obtained by each student in JEE- Main.
ii. Compute the percentile (P) of each student on the basis of aggregate marks in his/her own
board (B0) computed from the list of five subjects specified (each marked out of 100). The
percentile is to be computed among all students of the board whose subject combinations
meet the eligibility criteria of JEE-Main.
iii. Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India
level. Regard this as B1.
iv. Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the
set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this
as B2.
The normalized board score of the candidate will be computed as:
Bfinal = 0.5 * (B1 + B2)
For the purpose of admission to CFTIs where it has been decided to use the JEE Mains
performance and the Normalized Board performance in the 60:40 ratio, the composite
score for drawing the merit list will be computed as:
C = 0.6 * AO + 0.4 * Bfinal,
Five subjects to be used for normalization:-
1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology, Biotechnology and Computer Science
4. One language
5. Any subject other than the above four subjects.
In respect of 3, 4 and 5, the best mark in a given category will be chosen....
Check your results of jee main 2013 and your counselling eligibility by clicking this link :-
.....
Normalization Procedure for Class XII Board Marks
In view of large scale variations in the examination system in country, the JEE Interface
Group (JIG) decided that for this year (2013), 50% of Boards marks be normalized by
equating percentile amongst different boards/examining bodies and anchoring them to
All India JEE-Main percentiles, and 50% be normalized by equating each
Board’s/examining Body’s percentile with JEE(Main) percentile marks of respective
Boards /examining bodies.
Accordingly, the detailed procedure for normalization of Board marks will be as follows:-
i. Note down the aggregate marks (A0) obtained by each student in JEE- Main.
ii. Compute the percentile (P) of each student on the basis of aggregate marks in his/her own
board (B0) computed from the list of five subjects specified (each marked out of 100). The
percentile is to be computed among all students of the board whose subject combinations
meet the eligibility criteria of JEE-Main.
iii. Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India
level. Regard this as B1.
iv. Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the
set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this
as B2.
The normalized board score of the candidate will be computed as:
Bfinal = 0.5 * (B1 + B2)
For the purpose of admission to CFTIs where it has been decided to use the JEE Mains
performance and the Normalized Board performance in the 60:40 ratio, the composite
score for drawing the merit list will be computed as:
C = 0.6 * AO + 0.4 * Bfinal,
Five subjects to be used for normalization:-
1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology, Biotechnology and Computer Science
4. One language
5. Any subject other than the above four subjects.
In respect of 3, 4 and 5, the best mark in a given category will be chosen....
Check your results of jee main 2013 and your counselling eligibility by clicking this link :-
Counselling eligibilty according to jee main marks 2013
.....
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